Sleeper Density in Railways with solved example

sleeper density
sleeper density

Sleeper Density in Railways

sleeper density
sleeper density

Number of sleepers provided for one rail length of track is called sleeper density. If “N” is the length of one rail in meters,

Sleeper Density = N+ X , (X –> 3 to 6)

For a Broad Gauge track, total number of sleepers required for 1km length of railway track if sleeper density = N+5

Length of one rail = 12.8m =13m

Sleeper Density = N+5 = 13+ 5 = 18

Total number of sleepers required for 1km length = (18/12.8)x1000 = 1406 sleepers.

 

 

 

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About Anand Paul 253 Articles
...an Engineer and Tutor. Anand Paul is a bridge engineer at ch2m Global Design Center, Hyderabad. He is responsible for regional and local design projects. Committed to quality and timely delivery, he has been assigned multiple domain projects in Middle and India. Being a programmer, he is leading in-house spreadsheet development team. Apart from his routine, he runs CivilDigital.com, an exclusive Civil Engineering website.